A thermodynamic system is taken through the c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a cyclic process,the change in internal energy is zero,i.e.,$\Delta U = 0$.According to the first law of thermodynamics,$\Delta Q = \Delta U +

Vedclass · Accepted Answer

$2PV$

Vedclass · Answer

(A) In a cyclic process,the change in internal energy is zero,i.e.,$\Delta U = 0$.According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. Since $\Delta U = 0$,we have $\Delta Q = \Delta W$.The work done in a cyclic process is equal to the area enclosed by the cycle on the $P-V$ diagram.The cycle $ABCD$ is traversed in an anticlockwise direction,so the work done by the gas is negative.Area of the rectangle $ABCD = (	ext{change in volume}) 	imes (	ext{change in pressure}) = (3V - V) 	imes (2P - P) = (2V) 	imes (P) = 2PV$.Since the cycle is anticlockwise,$\Delta W = -2PV$.Thus,$\Delta Q = -2PV$.The negative sign indicates that heat is rejected by the system.Therefore,the heat rejected by the gas is $2PV$.

$A$ thermodynamic system is taken through the cycle $ABCD$ as shown in the figure. Heat rejected by the gas during the cycle is:

Similar Questions

Four moles of an ideal monoatomic gas undergoes a cyclic process $ABCA$ as shown in the figure. Find the ratio of the temperature of $A$ and $B$.

An ideal gas undergoes a cyclic process $ABCDA$ as shown in the given $p-V$ diagram. What is the magnitude of the amount of work done by the gas?

An ideal gas is taken through the cycle $A \to B \to C \to A$,as shown in the figure. If the net heat supplied to the gas in the cycle is $5\,J$,the work done by the gas in the process $C \to A$ is ...... $J$.

$A$ thermodynamic system undergoes a cyclic process $PQRSP$. The total work done by the system is..... $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module