A thief is running away on a straight road in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The speed of the thief's jeep is $v_t = 9 \, m/s$.The speed of the policeman's motorcycle is $v_p = 10 \, m/s$.The relative speed of the policeman

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) The speed of the thief's jeep is $v_t = 9 \, m/s$.The speed of the policeman's motorcycle is $v_p = 10 \, m/s$.The relative speed of the policeman with respect to the thief is $v_{rel} = v_p - v_t = 10 - 9 = 1 \, m/s$.The initial distance (separation) between them is $d = 100 \, m$.To catch the thief,the policeman must cover this relative distance at the relative speed.Time taken $t = \frac{d}{v_{rel}} = \frac{100 \, m}{1 \, m/s} = 100 \, s$.Therefore,it will take $100 \, seconds$ for the policeman to catch the thief.

Similar Questions

$A$ man on a rectilinearly moving cart,facing the direction of motion,throws a ball straight up with respect to himself.

$A$ man is $45 \, m$ behind the bus when the bus starts accelerating from rest with an acceleration of $2.5 \, m/s^2$. With what minimum velocity should the man start running to catch the bus?

Two cars $A$ and $B$ are travelling in the same direction with velocities $V_A$ and $V_B$ $(V_A > V_B)$. When the car $A$ is at a distance $S$ behind the car $B$,the driver of the car $A$ applies the brakes producing a uniform retardation $a$. There will be no collision when:

Vedclass Test Series

Exam Paper Generator

Online Exam Module