$A$ thin prism of glass is placed in air and water successively. If $_a\mu _g = 3/2$ and $_a\mu _w = 4/3$,then the ratio of the deviation produced by the prism for a small angle of incidence when placed in air and water is

$A$ thin glass prism of angle $9^{\circ}$ with refractive index $1.4$ is combined with another glass prism of refractive index $1.6$ as shown in the figure. The combination of the prisms provides dispersion without deviation. Determine the angle $(A)$ of the second prism. (in $^{\circ}$)

The angle of deviation for a ray passing through the given prism is $30^o$. If one half of the prism is removed,what will be the new angle of deviation in degrees?

The angle of minimum deviation for a prism of refractive index $1.5$ is equal to the angle of the prism. The angle of the prism is . . . . . . . $(\sin 48^{\circ} 36^{\prime} = 0.75)$

$A$ ray of light is incident at an angle of incidence '$i$' on one surface of a thin prism of small angle '$A$'. The ray emerges normally from the opposite surface. If the refractive index of the material of the prism is '$\mu$',the angle of incidence '$i$' is nearly equal to

Light rays from a source are incident on a glass prism of refractive index $\mu$ and prism angle $\alpha$. At near-normal incidence,the angle of deviation of the emerging rays is: