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(D) The induced electromotive force $(emf)$ in a conductor moving in a magnetic field is given by the motional $emf$ formula $e = B l v$,where $l$ is

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$2 R B V$ and $Q$ is at higher potential

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(D) The induced electromotive force $(emf)$ in a conductor moving in a magnetic field is given by the motional $emf$ formula $e = B l v$,where $l$ is the effective length of the conductor perpendicular to the velocity and the magnetic field.For a semicircular ring of radius $R$ moving with velocity $V$ perpendicular to a uniform magnetic field $B$,the effective length $l$ between the ends $M$ and $Q$ is the diameter of the semicircle,which is $2R$.Therefore,the induced $emf$ is $e = B(2R)V = 2RBV$.According to Lenz's law,the induced current will oppose the change in magnetic flux. As the ring moves out of the magnetic field,the flux through the loop decreases. To oppose this,the induced current will create a magnetic field in the same direction as the external field (into the page). By the right-hand rule,this corresponds to a current flowing from $M$ to $Q$ through the ring,making $Q$ the higher potential point.

$A$ thin semicircular conducting ring of radius $R$ is falling with its plane vertical in a horizontal magnetic induction $B$. At the position $MNQ$,the speed of the ring is $V$ and the potential difference developed across the ring is

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