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(B) The rate of radiated energy (power) is given by Stefan-Boltzmann law: $P = A \varepsilon \sigma T^4$.Here,the area $A$ of the square plate is $(10

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$1189$

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(B) The rate of radiated energy (power) is given by Stefan-Boltzmann law: $P = A \varepsilon \sigma T^4$.Here,the area $A$ of the square plate is $(10 	ext{ cm})^2 = (0.1 	ext{ m})^2 = 0.01 	ext{ m}^2$.The emissivity $\varepsilon = 1$,and Stefan's constant $\sigma = 5.67 	imes 10^{-8} 	ext{ W m}^{-2} 	ext{ K}^{-4}$.Given $P = 1134 	ext{ W}$.Substituting the values: $1134 = 0.01 	imes 1 	imes 5.67 	imes 10^{-8} 	imes T^4$.$1134 = 5.67 	imes 10^{-10} 	imes T^4$.$T^4 = \frac{1134}{5.67 	imes 10^{-10}} = 200 	imes 10^{10} = 2 	imes 10^{12}$.$T = (2 	imes 10^{12})^{1/4} = (2)^{1/4} 	imes 10^3 \approx 1.189 	imes 1000 = 1189 	ext{ K}$.

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