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(C) The current gain $\beta$ in common emitter configuration is related to $\alpha$ by the formula:$\beta = \frac{\alpha}{1 - \alpha} = \frac{0.96}{1

Vedclass · Accepted Answer

$26$

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(C) The current gain $\beta$ in common emitter configuration is related to $\alpha$ by the formula:$\beta = \frac{\alpha}{1 - \alpha} = \frac{0.96}{1 - 0.96} = \frac{0.96}{0.04} = 24$.The collector current $I_C$ is determined by the voltage drop across the collector resistor $R_C = 800\,\Omega$:$I_C = \frac{V_{drop}}{R_C} = \frac{0.5\ V}{800\,\Omega} = 0.000625\ A = 0.625 	imes 10^{-3}\ A$.The base current $I_B$ is related to the collector current by $I_C = \beta I_B$,so:$I_B = \frac{I_C}{\beta} = \frac{0.625 	imes 10^{-3}\ A}{24} \approx 0.02604 	imes 10^{-3}\ A$.$I_B \approx 26 	imes 10^{-6}\ A = 26\,\mu A$.

$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8\ V$ and the voltage drop across a resistor of $800\,\Omega$ in the collector circuit is $0.5\ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.

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