In an $n-p-n$ transistor,in $CE$ configuration:

An $n-p-n$ transistor has three leads $A, B$ and $C$. Connecting $B$ and $C$ by moist fingers,$A$ to the positive lead of an ammeter,and $C$ to the negative lead of the ammeter,one finds large deflection. Then,$A, B$ and $C$ refer respectively to

In an $n-p-n$ transistor circuit,the collector current is $20 \, mA$. If $90 \%$ of the emitted electrons reach the collector,calculate the emitter current and base current.

The voltage gain of a transistor in common emitter configuration is $160$. The resistances in base and collector sides of the circuit are $1 \text{ k}\Omega$ and $4 \text{ k}\Omega$ respectively. If the change in base current is $100 \mu A$, then the change in output current is:

In a transistor, if $\frac{I_C}{I_E} = \alpha$ and $\frac{I_C}{I_B} = \beta$. If $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$, then the value of $\beta$ lies between:

For a common-emitter amplifier, the voltage gain is $40$. Its input and output impedances are $100 \ \Omega$ and $400 \ \Omega$, respectively. The power gain of the $CE$ amplifier will be