In an n-p-n transistor circuit,the collector | vedclass

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(B) Given: Collector current $I_C = 20 \, mA$. Since $90 \%$ of the emitted electrons reach the collector,the current gain factor $\alpha = \frac{I_C}

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emitter current will be $22.2 \, mA$

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(B) Given: Collector current $I_C = 20 \, mA$. Since $90 \%$ of the emitted electrons reach the collector,the current gain factor $\alpha = \frac{I_C}{I_E} = 0.90$. Using the relation $I_C = \alpha I_E$,we find the emitter current: $I_E = \frac{I_C}{\alpha} = \frac{20 \, mA}{0.90} = 22.22 \, mA$. Using the relation $I_E = I_C + I_B$,we find the base current: $I_B = I_E - I_C = 22.22 \, mA - 20 \, mA = 2.22 \, mA$. Comparing with the given options,the emitter current is $22.2 \, mA$.

In an $n-p-n$ transistor circuit,the collector current is $20 \, mA$. If $90 \%$ of the emitted electrons reach the collector,calculate the emitter current and base current.

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