$A$ transverse wave of frequency $500 \,Hz$ and speed $100 \,m/s$ is travelling in the positive $x$-direction on a long string. At time $t=0 \,s$,the displacements at $x=0.0 \,m$ and at $x=0.25 \,m$ are $0.0 \,m$ and $0.02 \,m$,respectively. The displacement at $x=0.2 \,m$ at $t=5 \times 10^{-4} \,s$ is ............ $m$.

$A$ transverse wave is described by the equation $y = A \sin [2\pi (f t - x/\lambda ) ]$. The maximum particle velocity is equal to four times the wave velocity if:

For a wave equation $y = 10 \sin \pi (0.01x - 2.00t) \text{ cm}$,what is the maximum particle velocity in $\text{cm/sec}$?

$A$ wave represented by the given equation $Y = A\sin(10\pi x + 15\pi t + \frac{\pi}{3})$,where $x$ is in meters and $t$ is in seconds. The expression represents:

$A$ wave travelling along a string is described by,
$y(x, t) = 0.005 \sin (80.0 x - 3.0 t)$
In which the numerical constants are in $SI$ units ($0.005 \, m, 80.0 \, rad \, m^{-1},$ and $3.0 \, rad \, s^{-1}$). Calculate
$(a)$ the amplitude,
$(b)$ the wavelength,and
$(c)$ the period and frequency of the wave.
Also,calculate the displacement $y$ of the wave at a distance $x = 30.0 \, cm$ and time $t = 20 \, s$.

$A$ wave is given by the equation $y=(0.02) \sin (\pi x - 8 \pi t)$. The velocity of the wave is (where $y$ and $x$ are in meters and $t$ is in seconds). (in $m/s$)