A triangular target with sides measuring 5 , | vedclass

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(C) $1$. First,calculate the area of the square board: $	ext{Area of square} = 	ext{side}^2 = 20 \, cm 	imes 20 \, cm = 400 \, cm^2$.$2$. Next,iden

Vedclass · Accepted Answer

$\frac{3}{40}$

Vedclass · Answer

(C) $1$. First,calculate the area of the square board: $	ext{Area of square} = 	ext{side}^2 = 20 \, cm 	imes 20 \, cm = 400 \, cm^2$.$2$. Next,identify the type of triangle. Since $5^2 + 12^2 = 25 + 144 = 169 = 13^2$,the triangle is a right-angled triangle.$3$. Calculate the area of the triangular target: $	ext{Area of triangle} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 5 \, cm 	imes 12 \, cm = 30 \, cm^2$.$4$. The probability $P$ that a dart hitting the board hits the target is given by the ratio of the area of the target to the area of the board: $P = \frac{	ext{Area of triangle}}{	ext{Area of square}} = \frac{30}{400} = \frac{3}{40}$.

$A$ triangular target with sides measuring $5 \, cm, 12 \, cm$,and $13 \, cm$ is drawn on a square board with side $20 \, cm$. Find the probability that a dart hitting the board hits the target.

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