$A$ uniform cable of mass $M$ and length $L$ is placed on a horizontal surface such that its $(1/n)^{th}$ part is hanging below the edge of the surface. To lift the hanging part of the cable up to the surface,the work done should be

  • A
    $nMgL$
  • B
    $\frac{MgL}{2n^2}$
  • C
    $\frac{2MgL}{n^2}$
  • D
    $\frac{MgL}{n^2}$

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