A uniform conducting wire ABC has a mass of 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic force on a current-carrying wire is given by $\vec{F} = I(\vec{L}_{eff} 	imes \vec{B})$,where $\vec{L}_{eff}$ is the vector displace

Vedclass · Accepted Answer

$12\,m\,s^{-2}$ along the $x$-axis

Vedclass · Answer

(B) The magnetic force on a current-carrying wire is given by $\vec{F} = I(\vec{L}_{eff} 	imes \vec{B})$,where $\vec{L}_{eff}$ is the vector displacement from the starting point $A$ to the end point $C$.From the figure,the displacement vector $\vec{AC}$ has a magnitude of $3\,cm = 3 	imes 10^{-2}\,m$ and is directed along the positive $x$-axis.The magnetic field $\vec{B}$ is directed into the plane (negative $z$-direction,$-2\hat{k}\,T$).The effective length vector is $\vec{L}_{eff} = 3 	imes 10^{-2}\hat{i}\,m$.The force is $\vec{F} = I(\vec{L}_{eff} 	imes \vec{B}) = 2 	imes (3 	imes 10^{-2}\hat{i} 	imes -2\hat{k}) = 2 	imes (6 	imes 10^{-2}\hat{j}) = 12 	imes 10^{-2}\,N$ along the positive $y$-axis.Given mass $m = 10\,g = 10^{-2}\,kg$.The acceleration $a = \frac{F}{m} = \frac{12 	imes 10^{-2}}{10^{-2}} = 12\,m\,s^{-2}$ along the $y$-axis.Note: The provided options contain a discrepancy regarding the direction. Based on the calculation,the force and acceleration are along the $y$-axis.

$A$ uniform conducting wire $ABC$ has a mass of $10\,g$. $A$ current of $2\,A$ flows through it. The wire is kept in a uniform magnetic field $B = 2\,T$ directed into the plane of the paper. The acceleration of the wire will be

Similar Questions

Write the formula for the magnetic force acting on a current-carrying wire placed in a uniform magnetic field.

Find the force per unit length at point $P$. The current in the wire is $5 \, A$ and the distance between the parallel segments is $10 \, cm$.

$A$ square loop $ABCD$ of side length $L$ carrying a current $i$ is placed near and coplanar with a long straight conductor $XY$ carrying a current $I$. The distance between the wire $XY$ and the nearest side of the loop is $L/2$. The net force on the loop will be:

$A$ straight horizontal long wire carries $30 \ A$ current. The linear mass density of the wire is $45 \ g/m$. What is the magnitude of the magnetic field needed to balance the wire in air?

$A$ wire of length $L$ carries current $I$ along the $x$-axis. $A$ magnetic field $\vec{B} = B_0(\hat{i} - \hat{j} - \hat{k}) \text{ T}$ acts on the wire. The magnitude of the magnetic force acting on the wire is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module