$A$ uniform rod $AB$ of length $l$ and mass $m$ is free to rotate about point $A$. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about $A$ is $\frac{ml^2}{3}$,the initial angular acceleration of the rod will be:

  • A
    $\frac{3g}{2l}$
  • B
    $\frac{2g}{3l}$
  • C
    $g\frac{l}{2}$
  • D
    $\frac{3}{2}gl$

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