$A$ uniform wire (Young's modulus $2 \times 10^{11} \, Nm^{-2}$) is subjected to a longitudinal tensile stress of $5 \times 10^7 \, Nm^{-2}$. If the overall volume change in the wire is $0.02\%$,the fractional decrease in the radius of the wire is close to:

  • A
    $1.0 \times 10^{-4}$
  • B
    $1.5 \times 10^{-4}$
  • C
    $0.25 \times 10^{-4}$
  • D
    $5 \times 10^{-4}$

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Similar Questions

Match the following:
Column-$I$ Column-$II$
$(A)$ Shear modulus $(I)$ Resistance to change in volume
$(B)$ Shearing stress $(II)$ Proportionality constant
$(C)$ Elastic fatigue $(III)$ Tangential stress
$(D)$ Modulus of elasticity $(IV)$ Temporary loss of elastic property
$(V)$ Resistance to change against deformation force

The correct match is:

$A$ string of length $0.314 \text{ m}$ and Young's modulus $2 \times 10^{10} \text{ N/m}^2$ is connected to another string of length $B$ and Young's modulus both twice of those of $A$. This series combination of strings is then suspended from a rigid support and its free end is fixed to a load of mass $0.8 \text{ kg}$. The net change in length of the combination is . . . . . . $\text{mm}$. (radius of both the strings is $0.2 \text{ mm}$ and acceleration due to gravity $= 10 \text{ m/s}^2$) (Mass of both strings is to be neglected as compared to the mass of load)

$A$ wire of density $3 \times 10^3 \, kg/m^3$ requires a breaking stress of $10^6 \, N/m^2$ to break. What should be the length of the wire so that it breaks under its own weight? (Take $g = 10 \, m/s^2$)

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Mark the wrong statement.

$A$ light rod of length $200\,cm$ is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and has a cross-section of $0.1\,cm^2$,and the other is made of brass with a cross-section of $0.2\,cm^2$. At what distance from the steel wire should a weight be hung along the rod to produce equal stresses in both wires?

Difficult
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