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(A) The maximum tension in a vertical circular motion occurs at the lowest point of the path.At the lowest point,the tension $T$ is given by $T = mr\o

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(A) The maximum tension in a vertical circular motion occurs at the lowest point of the path.At the lowest point,the tension $T$ is given by $T = mr\omega^2 + mg$.Given: $T_{\max} = 3.7\,kg-wt = 3.7 	imes 10\,N = 37\,N$,$m = 500\,g = 0.5\,kg$,$r = 4\,m$,and $g = 10\,ms^{-2}$.Substituting the values into the equation:$37 = (0.5)(4)\omega^2 + (0.5)(10)$$37 = 2\omega^2 + 5$$32 = 2\omega^2$$\omega^2 = 16$$\omega = 4\,rad\,s^{-1}$.

$A$ weightless thread can bear a tension up to $3.7\,kg-wt$. $A$ stone of mass $500\,g$ is tied to it and revolved in a circular path of radius $4\,m$ in a vertical plane. If $g = 10\,ms^{-2}$,then the maximum angular velocity of the stone will be ......... $rad\,s^{-1}$

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