(A) The maximum tension the string can bear is $T_{max} = 3.7 \, kg \cdot wt = 3.7 \times 10 \, N = 37 \, N$.In a vertical circular motion,the tension

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(A) The maximum tension the string can bear is $T_{max} = 3.7 \, kg \cdot wt = 3.7 \times 10 \, N = 37 \, N$.In a vertical circular motion,the tension is maximum at the lowest point of the path.The formula for tension at the lowest point is $T = mg + m\omega^2r$.Given mass $m = 500 \, g = 0.5 \, kg$,radius $r = 4 \, m$,and $g = 10 \, m/s^2$.Substituting the values: $37 = (0.5 \times 10) + (0.5 \times \omega^2 \times 4)$.$37 = 5 + 2\omega^2$.$32 = 2\omega^2$.$\omega^2 = 16$.$\omega = 4 \, rad/s$.

Class 11 Physics Work, Energy, Power and Collision Vertical Circular Motion

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$A$ weightless thread can bear a tension of up to $3.7 \, kg \, wt$. $A$ stone of mass $500 \, g$ is tied to it and revolved in a circular path of radius $4 \, m$ in a vertical plane. If $g = 10 \, m/s^2$,then the maximum angular velocity of the stone will be ........ $rad/s$.

A
$4$
B
$16$
C
$\sqrt{21}$
D
$2$

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Vertical Circular Motion

The bob of a simple pendulum is of mass $10 \, g$. It is suspended with a thread of $1 \, m$. If we hold the bob so as to stretch the string horizontally and release it,what will be the tension at the lowest position? (Take $g = 10 \, m/s^2$)

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$A$ point mass '$m$' is moved in a vertical circle of radius '$r$' with the help of a string. The velocity of the mass is $\sqrt{7gr}$ at the lowest point. The tension in the string at the lowest point is .......... $mg$.

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$A$ weightless thread can bear a tension of up to $3.7 \, kg \, wt$. $A$ stone of mass $500 \, g$ is tied to it and revolved in a circular path of radius $4 \, m$ in a vertical plane. If $g = 10 \, m/s^2$,then the maximum angular velocity of the stone will be ........ $rad/s$.

Similar Questions

The bob of a simple pendulum is of mass $10 \, g$. It is suspended with a thread of $1 \, m$. If we hold the bob so as to stretch the string horizontally and release it,what will be the tension at the lowest position? (Take $g = 10 \, m/s^2$)

$A$ fighter plane is moving in a vertical circle of radius $r$. Its minimum velocity at the highest point of the circle will be

$A$ body is placed as shown in the figure. To complete one full vertical circular loop,the height $h$ must be:

$A$ point mass '$m$' is moved in a vertical circle of radius '$r$' with the help of a string. The velocity of the mass is $\sqrt{7gr}$ at the lowest point. The tension in the string at the lowest point is .......... $mg$.

$A$ bob of mass $m$ is suspended by a light string of length $L$. It is imparted a minimum horizontal velocity at the lowest point $A$ such that it just completes a full vertical circle,reaching the topmost position $B$. The ratio of kinetic energies $\frac{(\text{K.E.})_A}{(\text{K.E.})_B}$ is:

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