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(C) The current $I$ flowing through a conductor is given by the relation $I = neAv_d$, where $n$ is the number density of electrons, $e$ is the charge

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$v_P > v_Q$

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(C) The current $I$ flowing through a conductor is given by the relation $I = neAv_d$, where $n$ is the number density of electrons, $e$ is the charge of an electron, $A$ is the cross-sectional area, and $v_d$ is the drift speed.Since the current $I$ is steady and $n$ and $e$ are constant, we have $A v_d = 	ext{constant}$, which implies $v_d \propto \frac{1}{A}$.From the figure, the cross-sectional area at point $P$ $(A_P)$ is smaller than the cross-sectional area at point $Q$ $(A_Q)$.Therefore, since $A_P  v_Q$.

$A$ wire has a non-uniform cross-section as shown in the figure. $A$ steady current flows through it. The drift speed of electrons at points $P$ and $Q$ is $v_P$ and $v_Q$ respectively.

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