Define mobility and write its $SI$ unit.
(N/A) Mobility $(\mu)$ is defined as the magnitude of the drift velocity $(v_d)$ per unit electric field $(E)$.
Mathematically, $\mu = \frac{v_d}{E}$.
The $SI$ unit of drift velocity is $m/s$ and the $SI$ unit of electric field is $V/m$ or $N/C$.
Therefore, the $SI$ unit of mobility is $\frac{m/s}{V/m} = m^2 V^{-1} s^{-1}$ or $m^2 / (V \cdot s)$.
Mathematically, $\mu = \frac{v_d}{E}$.
The $SI$ unit of drift velocity is $m/s$ and the $SI$ unit of electric field is $V/m$ or $N/C$.
Therefore, the $SI$ unit of mobility is $\frac{m/s}{V/m} = m^2 V^{-1} s^{-1}$ or $m^2 / (V \cdot s)$.
Explore More
Similar Questions
What is relaxation time?
Easy
View SolutionIf a current of $80 \ A$ is passing through a straight conductor of length $10 \ m$,then the total momentum of electrons in the conductor is (mass of electron $= 9.1 \times 10^{-31} \ kg$ and charge of electron $= 1.6 \times 10^{-19} \ C$).
When a potential difference is applied across the ends of a linear metallic conductor,
Easy
View Solution$A$ conductor of length $1.5 \ m$ and area of cross-section $3 \times 10^{-5} \ m^2$ has an electrical resistance of $15 \ \Omega$. The current density in the conductor for an electric field of $21 \ Vm^{-1}$ is
$A$ current of $1.6\, A$ is flowing through a wire having a cross-sectional area of $1\, mm^2$. If the density of free electrons in the material of the wire is $10^{29}\, m^{-3}$,the drift velocity of the electrons will be:
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo