$A$ wire stretched between two rigid supports vibrates in its fundamental mode with a frequency of $50 \, Hz$. The mass of the wire is $30 \, g$ and its linear density is $4 \times 10^{-2} \, kg/m$. The speed of the transverse wave on the string is ...... $m/s$.

$A$ uniform thin rope of length $12 \, m$ and mass $6 \, kg$ hangs vertically from a rigid support and a block of mass $2 \, kg$ is attached to its free end. $A$ transverse short wavetrain of wavelength $6 \, cm$ is produced at the lower end of the rope. What is the wavelength of the wavetrain (in $cm$) when it reaches the top of the rope?

$A$ uniform string is suspended vertically. $A$ transverse pulse is created at the top of the string. Then:

$A$ transverse wave is passing through a string as shown in the figure. The mass density of the string is $1 \ kg/m^3$ and the cross-sectional area of the string is $0.01 \ m^2$. The equation of the wave in the string is $y = 2 \sin(20t - 10x)$. The hanging mass is (in $kg$):-

$A$ mass of $20\ kg$ is hanging with the support of two strings of the same linear mass density. Now,pulses are generated in both strings at the same time near the joint at the mass. The ratio of the time taken by a pulse to travel through string $1$ to that taken by a pulse on string $2$ is:

$A$ transverse pulse generated at the bottom of a uniform rope of length $L$ travels in an upward direction. The time taken by it to travel the full length of the rope will be