$A$ wire of mass $m$ and length $l$ is bent in the form of a circular ring. The moment of inertia of the ring about its axis is:

The moment of inertia of a rod of mass $M$ and length $L$ about an axis passing through its centre and perpendicular to it is $\frac{1}{12} ML^2$. The rod is bent in the middle so that the two halves make an angle of $60^o$. The moment of inertia of the bent rod about the same axis (passing through the original centre of the rod) would be:

Five masses,each of $2\, kg$,are placed on a horizontal circular disc,which can be rotated about a vertical axis passing through its centre. All the masses are equidistant from the axis at a distance of $10\, cm$. The moment of inertia of the whole system (in $g\cdot cm^2$) is: (Assume the disc is of negligible mass)

Two rings have their moments of inertia in the ratio $4 : 1$ and their diameters are in the ratio $4 : 1$. The ratio of their masses is

$A$ ring of mass $m$ and radius $r$ is melted and recast into a sphere. The moment of inertia of the sphere will be:

The moment of inertia of a circular wire of mass $M$ and radius $R$ about its diameter is .......