According to molecular orbital theory,the par | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electronic configuration of the $O_2$ molecule ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \p

Vedclass · Accepted Answer

Unpaired electrons in the antibonding $\pi$ molecular orbital

Vedclass · Answer

(D) The electronic configuration of the $O_2$ molecule ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. According to Hund's rule,the last two electrons enter the degenerate antibonding $\pi^*$ molecular orbitals singly. These two unpaired electrons in the $\pi^* 2p_x$ and $\pi^* 2p_y$ orbitals are responsible for the paramagnetic nature of the $O_2$ molecule.

According to molecular orbital theory,the paramagnetism of the $O_2$ molecule is due to the presence of

Similar Questions

What is the bond order of $O_2^{2-}$?

Bond order of $He_{2}$, $He_{2}^{+}$ and $He_{2}^{2+}$ are respectively:

Provide the electron configuration, bond order, magnetic property, and energy level diagram for the Boron $(B_{2})$ molecule, and discuss its existence.

How many of the following species have the bond order $2$?
$C_2, B_2^{2-}, N_2^{2+}, CN^{+}, NO^{-}, O_2, C_2^{+}$

The correct molecular orbital diagram for $F_2$ molecule in the ground state is

Vedclass Test Series

Exam Paper Generator

Online Exam Module