Acetyl chloride is reduced with $LiAlH_4$. The product formed is:

  • A
    Methyl alcohol
  • B
    Ethyl alcohol
  • C
    Acetaldehyde
  • D
    Acetone

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Similar Questions

When acetyl chloride $(CH_3COCl)$ is reduced with $LiAlH_4$,the product formed is:

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