When acetyl chloride $(CH_3COCl)$ is reduced with $LiAlH_4$,the product formed is:

Identify $C$ in the following sequence of reactions:
$2\text{-methylcyclohexanecarboxylic acid}$ $\xrightarrow{SOCl_2} A$ $\xrightarrow{NH_3} B$ $\xrightarrow{P_4O_{10}, \text{heat}} C(C_8H_{13}N)$

The major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

Identify the major product $P$ in the following reaction:
$CH_2=C(OLi)-CH=C(OLi)OEt \xrightarrow[(ii) H_3O^+]{(i) CH_3CH_2I / THF} P$

Consider the following molecules $:$
$(p) \ CH_3-CH_2-COCl$
$(q) \ CH_3-CH_2-CO-O-COCH_3$
$(r) \ CH_3-CH_2-CO-OCH_2-CH_3$
$(s) \ CH_3-CH_2-CONH_2$
The correct order of rate of hydrolysis is $:$

Propanoic acid undergoes the $HVZ$ reaction to give $2-$chloropropanoic acid. The product obtained is: