Addition of $HCl$ does not obey Anti-Markovnikov's rule because

Consider the following reactions. What is $A$?
| Reaction | Observation |
| :--- | :--- |
| $A \ (C_7H_{14}) \xrightarrow{\text{ozonolysis}} B + C$ | |
| $B \xrightarrow{I_2 + NaOH, \Delta} \text{yellow ppt}$ | |
| $B \xrightarrow{Ag_2O, \Delta} \text{silver mirror}$ | |
| $C \xrightarrow{I_2 + NaOH, \Delta} \text{no yellow ppt}$ | |
| $C$ $\xrightarrow{LiAlH_4} D$ $\xrightarrow{\text{anhydrous } ZnCl_2, \text{conc. } HCl} \text{white turbidity within 5 minutes}$ | |

The product $(A)$ is:

Hydration of $3$-phenylbut$-1$-ene in dil. $H_2SO_4$ will give mainly

Reagent $A$ may be:

The reaction $CH_2 = CH_2 + H_2 \xrightarrow[{250 - 300 \, ^oC}]{{Ni}} CH_3 - CH_3$ is known as: