Aditya invests Rs. 50,000 in a fixed deposit | vedclass

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(C) Step $1$: Calculate the amount after $2$ years of compound interest $(C.I.)$.Amount $A = P(1 + R/100)^n$$A = 50000(1 + 10/100)^2 = 50000(1.1)^2 =

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$82280$

Vedclass · Answer

(C) Step $1$: Calculate the amount after $2$ years of compound interest $(C.I.)$.Amount $A = P(1 + R/100)^n$$A = 50000(1 + 10/100)^2 = 50000(1.1)^2 = 50000 	imes 1.21 = Rs. 60500$.Step $2$: Calculate the simple interest $(S.I.)$ on this amount for $3$ years at $12 \%$ per annum.$S.I. = (P 	imes R 	imes T) / 100$$S.I. = (60500 	imes 12 	imes 3) / 100 = 605 	imes 36 = Rs. 21780$.Step $3$: Calculate the final total amount.Final Amount = Principal for $S.I. + S.I. = 60500 + 21780 = Rs. 82280$.

Aditya invests $Rs. 50,000$ in a fixed deposit at $10 \%$ $C.I.$ for $2$ years. At the end of $2$ years,she puts the money in another deposit at $12 \%$ $S.I.$ for $3$ years. What was the final value (in $Rs.$) of the initial investment?

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