Alkylamine dissolves in hydrochloric acid to | vedclass

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Question

(D) Alkylamine $(R-NH_2)$ reacts with hydrochloric acid $(HCl)$ to form alkylammonium chloride $([R-NH_3]^+Cl^-)$.In the alkylammonium ion $([R-NH_3]^

Vedclass · Accepted Answer

Quadricovalent,Unielectrovalent

Vedclass · Answer

(D) Alkylamine $(R-NH_2)$ reacts with hydrochloric acid $(HCl)$ to form alkylammonium chloride $([R-NH_3]^+Cl^-)$.In the alkylammonium ion $([R-NH_3]^+)$,the nitrogen atom forms $4$ covalent bonds (three with hydrogen atoms and one with the alkyl group),making it quadricovalent.Since the nitrogen atom carries a positive charge and is part of an ionic salt,it exhibits unielectrovalent character.Therefore,the nitrogen in the salt is both quadricovalent and unielectrovalent.

Alkylamine dissolves in hydrochloric acid to form alkylammonium chloride. The nitrogen in the latter salt is:

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