Although Cr^{3+} and Co^{2+} ions have the sa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Both $Cr^{3+}$ $(3d^3)$ and $Co^{2+}$ $(3d^7)$ have $3$ unpaired electrons.According to the spin-only formula,$\mu = \sqrt{n(n+2)} \ B.M.$,both sh

Vedclass · Accepted Answer

Due to orbital contribution in $Co^{2+}$ ion.

Vedclass · Answer

(B) Both $Cr^{3+}$ $(3d^3)$ and $Co^{2+}$ $(3d^7)$ have $3$ unpaired electrons.According to the spin-only formula,$\mu = \sqrt{n(n+2)} \ B.M.$,both should have a magnetic moment of $\sqrt{3(3+2)} = \sqrt{15} \approx 3.87 \ B.M.$However,$Cr^{3+}$ has a symmetrical $t_{2g}^3$ configuration,resulting in no orbital contribution to the magnetic moment.In contrast,$Co^{2+}$ has an unsymmetrical configuration,which leads to a significant orbital contribution,increasing the observed magnetic moment to approximately $4.87 \ B.M.$

Although $Cr^{3+}$ and $Co^{2+}$ ions have the same number of unpaired electrons,why is the magnetic moment of $Cr^{3+}$ $3.87 \ B.M.$ and that of $Co^{2+}$ $4.87 \ B.M.?$

Similar Questions

Which of the following is not correctly matched?

Which of the following complexes will show coordination isomerism?
$A. [Ag(NH_3)_2][Ag(CN)_2]$
$B. [Co(NH_3)_6][Cr(CN)_6]$
$C. [Co(NH_3)_6][Co(CN)_6]$
$D. [Fe(NH_3)_6][Co(CN)_6]$
$E. [Co(NH_3)_6][Fe(CN)_6]$
Choose the correct answer from the options given below:

Which of the following coordination compounds would exhibit optical isomerism?

Which one of the following has an optical isomer?
$(en = \text{ethylenediamine})$

Identify the complex compound$(s)$ which is/are optically active and whose optical activity does not depend upon the orientation of the ligands around the metal cation:
$(i). [CoCl_3(NH_3)_3]$
$(ii). [Co(en)_3]Cl_3$
$(iii). [Co(C_2O_4)_2(NH_3)_2]^-$
$(iv). [CrCl_2(NH_3)_2(en)]^+$

Vedclass Test Series

Exam Paper Generator

Online Exam Module