Although $+3$ oxidation state is most common in lanthanoids, cerium still shows $+4$ oxidation state because:
- AAfter losing one more electron, it acquires $4f^{14}$ electronic configuration.
- BIts nearest inert gas is Radon.
- CAfter losing one more electron, it acquires $4f^0$ electronic configuration.
- DIts atomic number is $61$.
Explore More
Similar Questions
Fill in the blanks given below:
$(i)$ Neptunium and Plutonium are obtained from ............ .
$(ii)$ Lanthanoid series and Actinoid series are known as ............ .
$(iii)$ The main energy level of an atom is called ............ .
$(iv)$ Elements that possess both metallic and non-metallic properties are called ............ .
$(i)$ Neptunium and Plutonium are obtained from ............ .
$(ii)$ Lanthanoid series and Actinoid series are known as ............ .
$(iii)$ The main energy level of an atom is called ............ .
$(iv)$ Elements that possess both metallic and non-metallic properties are called ............ .
Easy
View SolutionThe main reason for the actinoids exhibiting a larger number of oxidation states than the lanthanoids is:
Medium
View SolutionWrite the atomic number,name,symbol,and electronic configuration of Actinium and the Actinoids.
Difficult
View SolutionThe lanthanide contraction relates to
Medium
View SolutionWhich of the following elements is not an actinoid?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo