Write the atomic number,name,symbol,and electronic configuration of Actinium and the Actinoids.

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(N/A) $(i)$ The atomic number,name,symbol,and electronic configuration of $Ac$ and $14$ Actinoids are given in the table below:
Atomic Number $(Z)$SymbolNameElectronic Configuration
$89$$Ac$Actinium$[Rn]^{86} 6d^1 7s^2$
$90$$Th$Thorium$[Rn]^{86} 6d^2 7s^2$
$91$$Pa$Protactinium$[Rn]^{86} 5f^2 6d^1 7s^2$
$92$$U$Uranium$[Rn]^{86} 5f^3 6d^1 7s^2$
$93$$Np$Neptunium$[Rn]^{86} 5f^4 6d^1 7s^2$
$94$$Pu$Plutonium$[Rn]^{86} 5f^6 7s^2$
$95$$Am$Americium$[Rn]^{86} 5f^7 7s^2$
$96$$Cm$Curium$[Rn]^{86} 5f^7 6d^1 7s^2$
$97$$Bk$Berkelium$[Rn]^{86} 5f^9 7s^2$
$98$$Cf$Californium$[Rn]^{86} 5f^{10} 7s^2$
$99$$Es$Einsteinium$[Rn]^{86} 5f^{11} 7s^2$
$100$$Fm$Fermium$[Rn]^{86} 5f^{12} 7s^2$
$101$$Md$Mendelevium$[Rn]^{86} 5f^{13} 7s^2$
$102$$No$Nobelium$[Rn]^{86} 5f^{14} 7s^2$
$103$$Lr$Lawrencium$[Rn]^{86} 5f^{14} 6d^1 7s^2$

$(ii)$ It is assumed that all Actinoids have a $7s^2$ electronic configuration,and the $5f$ and $6d$ subshells are filled differently.
$14$ electrons can be filled in $5f$ orbitals.
Thorium $(Th)$,$Z=90$ has $5f^0$,but from Protactinium $(Pa)$,$Z=91$ onwards,electrons are filled in the $5f$ subshell,and finally,in Lawrencium $(Lr)$,$Z=103$,the $5f$ orbitals are completely filled with a $5f^{14}$ configuration.

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