Which of the following pairs show +2 oxidatio | vedclass

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Question

(B) The general oxidation state of lanthanoids is $+3$. However,some lanthanoids exhibit $+2$ or $+4$ oxidation states due to stable electronic config

Vedclass · Accepted Answer

$_{63}Eu$ and $_{70}Yb$

Vedclass · Answer

(B) The general oxidation state of lanthanoids is $+3$. However,some lanthanoids exhibit $+2$ or $+4$ oxidation states due to stable electronic configurations (half-filled or fully-filled $f$-orbitals). $Eu$ $(Z = 63)$ has the configuration $[Xe] 4f^7 6s^2$. By losing two electrons,it forms $Eu^{2+}$ $(4f^7)$,which is stable due to the half-filled $f$-subshell. $Yb$ $(Z = 70)$ has the configuration $[Xe] 4f^{14} 6s^2$. By losing two electrons,it forms $Yb^{2+}$ $(4f^{14})$,which is stable due to the fully-filled $f$-subshell. Therefore,the pair showing $+2$ oxidation state is $_{63}Eu$ and $_{70}Yb$.

Which of the following pairs show $+2$ oxidation state?

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