Most basic hydroxide among the following is

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(D) Due to lanthanide contraction,the ionic radius of $M^{3+}$ ions decreases as the atomic number increases from $Ce$ to $Lu$.As the size of the $M^{

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$Ce(OH)_3$

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(D) Due to lanthanide contraction,the ionic radius of $M^{3+}$ ions decreases as the atomic number increases from $Ce$ to $Lu$.As the size of the $M^{3+}$ ion decreases,the covalent character of the $M-OH$ bond increases,which leads to a decrease in the basic strength of the hydroxides.The order of ionic radii is $Ce^{3+} > Eu^{3+} > Yb^{3+} > Lu^{3+}$.Therefore,the order of basic strength of the hydroxides is $Ce(OH)_3 > Eu(OH)_3 > Yb(OH)_3 > Lu(OH)_3$.Thus,$Ce(OH)_3$ is the most basic hydroxide.

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