Aluminium reacts with $NaOH$ and forms compound '$X$'. If the coordination number of aluminium in '$X$' is $6$, the correct formula of $X$ is:

  • A
    $[Al(H_2O)_4(OH)_2]^+$
  • B
    $[Al(H_2O)_3(OH)_3]$
  • C
    $[Al(H_2O)_2(OH)_4]^-$
  • D
    $[Al(H_2O)_6](OH)_3$

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