Consider the compounds,$BCl_3$ and $CCl_4$. How will they behave with water? Justify.
(N/A) $BCl_3$ acts as a Lewis acid and readily undergoes hydrolysis to form boric acid:
$BCl_3 + 3H_2O \longrightarrow 3HCl + B(OH)_3$
$CCl_4$ resists hydrolysis completely because carbon lacks vacant $d$-orbitals to accept electrons from water molecules to form an intermediate. Thus,when mixed,they form separate layers:
$CCl_4 + H_2O \longrightarrow \text{No reaction}$
$BCl_3 + 3H_2O \longrightarrow 3HCl + B(OH)_3$
$CCl_4$ resists hydrolysis completely because carbon lacks vacant $d$-orbitals to accept electrons from water molecules to form an intermediate. Thus,when mixed,they form separate layers:
$CCl_4 + H_2O \longrightarrow \text{No reaction}$
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