Aluminium chloride in acidified aqueous solut | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $AlCl_{3}$ in an acidified aqueous solution undergoes hydration to form the octahedral complex $[Al(H_{2}O)_{6}]^{3+}$.The electronic configuratio

Vedclass · Accepted Answer

$[Al(H_{2}O)_{6}]^{3+}, sp^{3}d^{2}$

Vedclass · Answer

(A) $AlCl_{3}$ in an acidified aqueous solution undergoes hydration to form the octahedral complex $[Al(H_{2}O)_{6}]^{3+}$.The electronic configuration of $Al^{3+}$ is $[Ne] \ 3s^{0} \ 3p^{0} \ 3d^{0}$.To accommodate six water ligands,the $Al^{3+}$ ion utilizes one $3s$,three $3p$,and two $3d$ orbitals,resulting in $sp^{3}d^{2}$ hybridisation.Therefore,$A = [Al(H_{2}O)_{6}]^{3+}$ and $B = sp^{3}d^{2}$.

Aluminium chloride in acidified aqueous solution forms a complex $A$,in which hybridisation of $Al$ is $B$. What are $A$ and $B$,respectively?

Similar Questions

The hybridization of $Ag^+$ in the linear complex $[Ag(NH_3)_2]^+$ is

Which of the following complexes involves $4p$ orbitals for hybridization?

$EDTA^{4-}$ is the ethylenediaminetetraacetate ion. The total number of $N-Co-O$ bond angles in the $[Co(EDTA)]^{-}$ complex ion is:

Predict the number of unpaired electrons in the square planar $[Pt(CN)_{4}]^{2-}$ ion.

Which of the following is not a square planar complex?

Vedclass Test Series

Exam Paper Generator

Online Exam Module