Ammonium acetate reacts with acetic acid at $110\,^{\circ}C$ to form:

  • A
    Acetamide
  • B
    Formamide
  • C
    Ammonium cyanate
  • D
    Urea

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Similar Questions

$4$-Pentenoic acid when treated with $I_2$ and $NaHCO_3$ gives:

Arrange the following compounds in increasing order of their $pK_{a}$ values:
$(a)$ $p$-nitrobenzoic acid
$(b)$ $p$-methoxybenzoic acid
$(c)$ $p$-nitrophenol
$(d)$ benzoic acid

$EtO-CO-OEt \xrightarrow[(2) H_3O^{+}]{(1) CH_3MgBr \text{ (excess)}} (A)$,Product $(A)$ is:

Derive an equation for $pK_{a}$ for carboxylic acid compounds. Also,give the relation between $pK_{a}$ and acidic strength.

Difficult
View Solution

Predict the product of the reaction:
$\text{2-oxocyclohexanecarboxylic acid} \xrightarrow[{(2)\Delta }]{{(1){H_3}{O^ + }}}$

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