Among KO_2,NO_2^-,BaO_2 and NO_2^+,an unpaire | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configurations are as follows:$1$. $KO_2$ contains the superoxide ion $O_2^-$. The molecular orbital configuration of $O_2^-$ is $\

Vedclass · Accepted Answer

$KO_2$ only

Vedclass · Answer

(C) The electronic configurations are as follows:$1$. $KO_2$ contains the superoxide ion $O_2^-$. The molecular orbital configuration of $O_2^-$ is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$. It has one unpaired electron.$2$. $NO_2^-$ has $5 + 6(2) + 1 = 18$ valence electrons. All electrons are paired.$3$. $BaO_2$ contains the peroxide ion $O_2^{2-}$. The configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$. All electrons are paired.$4$. $NO_2^+$ has $5 + 6(2) - 1 = 16$ valence electrons. All electrons are paired.Therefore,only $KO_2$ contains an unpaired electron.

Among $KO_2$,$NO_2^-$,$BaO_2$ and $NO_2^+$,an unpaired electron is present in:

Similar Questions

Correct order of $C-O$ bond length is:

Which of the following species is not paramagnetic?

Which of the following is diamagnetic?

If the magnetic moment of a dioxygen species is $1.73 \; B.M$,it may be

If the bond order in $C_2$ is '$x$',then the bond order in $B_2$ and $O_2$,respectively,are

Vedclass Test Series

Exam Paper Generator

Online Exam Module