Among the given cations,the most stable carbo | vedclass

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(B) The stability order of carbocations is $3^{\circ} > 2^{\circ} > 1^{\circ} > 	ext{methyl}$.$(CH_3)_3C^{+}$ is a $3^{\circ}$ (tert-butyl) carbocati

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tert-butyl

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(B) The stability order of carbocations is $3^{\circ} > 2^{\circ} > 1^{\circ} > 	ext{methyl}$.$(CH_3)_3C^{+}$ is a $3^{\circ}$ (tert-butyl) carbocation,$(CH_3)_2CH^{+}$ is a $2^{\circ}$ (sec-butyl) carbocation,and $CH_3CH_2^+$ is a $1^{\circ}$ (n-butyl) carbocation.Since the stability of carbocations increases with the number of alkyl groups attached to the positively charged carbon due to the inductive effect and hyperconjugation,the $3^{\circ}$ carbocation is the most stable.Therefore,the correct option is $(b)$.

Among the given cations,the most stable carbonium ion is

Similar Questions

Consider the following carbocations:
$I. C_6H_5CH_2^+$
$II. CH_2=CH^+$
$III. CH_3-CH^+(CH_3)$
$IV. CH_3-CH_2^+$
$V. HC \equiv C^+$
Arrange the above carbocations in the order of decreasing stability.

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The correct order of decreasing stability of the following carbocations is:
$I. CH_3-CH^{+}-CH_3$
$II. CH_3-CH^{+}-OCH_3$
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