Among the given compounds I, II, III,the corr | vedclass

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(A) The bond dissociation energy is inversely proportional to the stability of the free radical formed after the homolytic fission of the $C-H$ bond.$

Vedclass · Accepted Answer

$II > I > III$

Vedclass · Answer

(A) The bond dissociation energy is inversely proportional to the stability of the free radical formed after the homolytic fission of the $C-H$ bond.$1$. The $C-H$ bond in $II$ is an $sp-H$ bond (alkynyl),which is the most stable radical precursor but the radical itself is highly unstable due to high $s$-character.$2$. The $C-H$ bond in $I$ is an $sp^2-H$ bond (aryl).$3$. The $C-H$ bond in $III$ is an $sp^2-H$ bond (cyclopropenyl),which forms a stable aromatic cyclopropenyl radical.The stability order of the radicals formed is: $III > I > II$.Therefore,the bond dissociation energy order is: $II > I > III$.

Among the given compounds $I, II, III$,the correct order of bond dissociation energy of the $C-H$ bond marked with $*$ is:

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