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(A) The elevation in boiling point is a colligative property,which depends on the van't Hoff factor $(i)$.$\Delta T_b = i 	imes K_b 	imes m$.For a g

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$1 \ m \ FeCl_3$

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(A) The elevation in boiling point is a colligative property,which depends on the van't Hoff factor $(i)$.$\Delta T_b = i 	imes K_b 	imes m$.For a given molality $(m)$ and solvent,$\Delta T_b$ is directly proportional to $i$.- For $1 \ m \ FeCl_3$,$i = 4$ $(Fe^{3+} + 3Cl^-)$.- For $1 \ m \ NaCl$,$i = 2$ $(Na^+ + Cl^-)$.- For $1 \ m \ BaCl_2$,$i = 3$ $(Ba^{2+} + 2Cl^-)$.- For $1 \ m \ 	ext{urea}$,$i = 1$ (non-electrolyte).Since $FeCl_3$ has the highest van't Hoff factor $(i = 4)$,it will show the highest elevation in boiling point,and thus the highest boiling point. The correct option is $A$.

Among the given solutions,which one has the highest boiling point under similar conditions?

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