Amongst [Ni(H_{2}O)_{6}]^{2+}, [Ni(PPh_{3})_{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Species having unpaired electrons are paramagnetic.$Ni$ has atomic number $28$, electronic configuration $[Ar] 3d^{8} 4s^{2}$.$1$. $[Ni(H_{2}O)_{6

Vedclass · Accepted Answer

$[Ni(H_{2}O)_{6}]^{2+}$ and $[Ni(PPh_{3})_{2}Cl_{2}]$

Vedclass · Answer

(A) Species having unpaired electrons are paramagnetic.$Ni$ has atomic number $28$, electronic configuration $[Ar] 3d^{8} 4s^{2}$.$1$. $[Ni(H_{2}O)_{6}]^{2+}$: $Ni$ is in $+2$ oxidation state $(3d^{8})$. $H_{2}O$ is a weak field ligand, so no pairing occurs. It has $2$ unpaired electrons (Paramagnetic).$2$. $[Ni(PPh_{3})_{2}Cl_{2}]$: $Ni$ is in $+2$ oxidation state $(3d^{8})$. It is a tetrahedral complex. Due to the presence of $Cl^{-}$ ligands, it remains high spin with $2$ unpaired electrons (Paramagnetic).$3$. $[Ni(CO)_{4}]$: $Ni$ is in $0$ oxidation state $(3d^{8} 4s^{2})$. $CO$ is a strong field ligand, causing pairing of all electrons. It has $0$ unpaired electrons (Diamagnetic).$4$. $[Ni(CN)_{4}]^{2-}$: $Ni$ is in $+2$ oxidation state $(3d^{8})$. $CN^{-}$ is a strong field ligand, causing pairing of electrons. It has $0$ unpaired electrons (Diamagnetic).Thus, $[Ni(H_{2}O)_{6}]^{2+}$ and $[Ni(PPh_{3})_{2}Cl_{2}]$ are paramagnetic.

Amongst $[Ni(H_{2}O)_{6}]^{2+}$, $[Ni(PPh_{3})_{2}Cl_{2}]$, $[Ni(CO)_{4}]$ and $[Ni(CN)_{4}]^{2-}$, the paramagnetic species are

Similar Questions

The magnetic moment of a transition metal ion is $\sqrt{15} \ \text{BM}$. Therefore,the number of unpaired electrons present in it,is:

Which of the following compounds is colored but does not contain any unpaired electrons?

The complex compounds $[Co(NH_3)_5 SO_4] Br$ and $[Co(NH_3)_5 Br] SO_4$ are

The total number of possible isomers for the complex compound $[Cu^{II}(NH_3)_4][Pt^{II}Cl_4]$ are

Which of the following statements is true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module