The total number of possible isomers for the | vedclass

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(D) The given complex is a coordination isomer. The possible isomers are formed by the exchange of ligands between the two coordination spheres:$1. [C

Vedclass · Accepted Answer

$6$

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(D) The given complex is a coordination isomer. The possible isomers are formed by the exchange of ligands between the two coordination spheres:$1. [Cu(NH_3)_4][PtCl_4]$$2. [Cu(NH_3)_3Cl][PtCl_3(NH_3)]$$3. [Cu(NH_3)_2Cl_2][PtCl_2(NH_3)_2]$ (cis-isomer)$4. [Cu(NH_3)_2Cl_2][PtCl_2(NH_3)_2]$ (trans-isomer)$5. [Cu(NH_3)Cl_3][PtCl(NH_3)_3]$$6. [Pt(NH_3)_4][CuCl_4]$Thus,the total number of possible isomers is $6$.

The total number of possible isomers for the complex compound $[Cu^{II}(NH_3)_4][Pt^{II}Cl_4]$ are

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