An $A.C.$ source is connected to a series $LCR$ circuit. If the voltage across $R$ is $40 \,V$, the voltage across $L$ is $80 \,V$, and the voltage across $C$ is $40 \,V$, then the e.m.f. '$e$' of the $A.C.$ source is:

  • A
    $40 \,V$
  • B
    $40 \sqrt{2} \,V$
  • C
    $80 \,V$
  • D
    $160 \,V$

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