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(B) The excess pressure inside an air bubble at a depth $h$ in a liquid is given by the sum of the pressure due to the liquid column and the excess pr

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$1800$

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(B) The excess pressure inside an air bubble at a depth $h$ in a liquid is given by the sum of the pressure due to the liquid column and the excess pressure due to surface tension.For an air bubble in a liquid, there is only one free surface.Excess pressure due to surface tension is given by $\Delta P_s = \frac{2S}{R}$.Pressure due to depth is given by $\Delta P_h = ho g h$.Total excess pressure $\Delta P = \frac{2S}{R} + ho g h$.Given: $S = 0.1 \ N \ m^{-1}$, $R = 1 \ mm = 1 	imes 10^{-3} \ m$, $ho = 2000 \ kg \ m^{-3}$, $h = 8 \ cm = 8 	imes 10^{-2} \ m$, and $g = 10 \ m \ s^{-2}$.Substituting the values:$\Delta P = \frac{2 	imes 0.1}{1 	imes 10^{-3}} + (2000 	imes 10 	imes 8 	imes 10^{-2})$$\Delta P = 200 + 1600 = 1800 \ N \ m^{-2}$.

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