An alcohol of formula $C_9H_{12}O$ reacts with $Na_2Cr_2O_7$ to form a compound having formula $C_9H_{10}O$. The original alcohol might be

  • A
    $Ph-CH_2-CH_2-CH_2-OH$
  • B
    $Ph-CH(OH)-CH_2-CH_3$
  • C
    $Ph-C(CH_3)_2-OH$
  • D
    $Ph-CH(CH_3)-CH_2OH$

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