An alkene X (C_4H_8) does not exhibit cis-tra | vedclass

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(C) $1$. The alkene $X$ is $C_4H_8$. The isomers of $C_4H_8$ are but$-1-$ene,but$-2-$ene,and $2-$methylpropene.$2$. But$-2-$ene exhibits cis-trans iso

Vedclass · Accepted Answer

$3-$bromobut$-1-$ene

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(C) $1$. The alkene $X$ is $C_4H_8$. The isomers of $C_4H_8$ are but$-1-$ene,but$-2-$ene,and $2-$methylpropene.$2$. But$-2-$ene exhibits cis-trans isomerism. But$-1-$ene does not exhibit cis-trans isomerism.$3$. $2-$methylpropene $(CH_2=C(CH_3)_2)$ also does not exhibit cis-trans isomerism.$4$. However,the reaction of $X$ with $Br_2$ in the presence of $UV$ light is a free-radical substitution reaction (allylic bromination).$5$. For but$-1-$ene $(CH_2=CH-CH_2-CH_3)$,the allylic position is $C_3$. Bromination at the allylic position gives $3-$bromobut$-1-$ene.$6$. Therefore,$X$ is but$-1-$ene and $Y$ is $3-$bromobut$-1-$ene.

An alkene $X$ $(C_4H_8)$ does not exhibit cis-trans isomerism. Reaction of $X$ with $Br_2$ in the presence of $UV$ light gives $Y$. What is $Y$?

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