An alkene gives two moles of HCHO,one mole of | vedclass

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(D) The products of ozonolysis are $2$ moles of $HCHO$,$1$ mole of $CO_2$,and $1$ mole of $CH_3COCHO$. By joining the carbonyl groups of these product

Vedclass · Accepted Answer

$CH_2=C=C(CH_3)-CH=CH_2$

Vedclass · Answer

(D) The products of ozonolysis are $2$ moles of $HCHO$,$1$ mole of $CO_2$,and $1$ mole of $CH_3COCHO$. By joining the carbonyl groups of these products with double bonds,we can reconstruct the original alkene structure. The fragments are: $H_2C=O$,$O=C=O$,$O=C(CH_3)-CH=O$,and $O=CH_2$. Removing the oxygen atoms and connecting the carbon atoms at the carbonyl sites with double bonds results in the structure: $CH_2=C=C(CH_3)-CH=CH_2$. Thus,the correct structure is $CH_2=C=C(CH_3)-CH=CH_2$.

An alkene gives two moles of $HCHO$,one mole of $CO_2$,and one mole of $CH_3COCHO$ on ozonolysis. What is its structure?

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