An aqueous pink solution of Cobalt $(II)$ chloride changes to deep blue on addition of excess of $HCl$. This is because:

  • A
    $[Co(H_2O)_6]^{2+}$ is transformed into $[CoCl_6]^{4-}$
  • B
    $[Co(H_2O)_6]^{2+}$ is transformed into $[CoCl_4]^{2-}$
  • C
    Tetrahedral complexes have larger crystal field splitting than octahedral complexes
  • D
    Octahedral complexes have larger crystal field splitting than square planar complexes

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