An aqueous solution of a salt X turns blood r | vedclass

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(B) The presence of $Fe^{3+}$ ions is indicated by the blood-red color formed with $CNS^{-}$ ions: $Fe^{3+} + 3CNS^{-} 	o Fe(CNS)_3$ (Ferric thiocyan

Vedclass · Accepted Answer

$FeCl_3$

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(B) The presence of $Fe^{3+}$ ions is indicated by the blood-red color formed with $CNS^{-}$ ions: $Fe^{3+} + 3CNS^{-} 	o Fe(CNS)_3$ (Ferric thiocyanate,blood-red coloration).$Fe^{3+}$ ions react with $K_4[Fe(CN)_6]$ to form a blue precipitate (Prussian blue): $4Fe^{3+} + 3[Fe(CN)_6]^{4-} 	o Fe_4[Fe(CN)_6]_3$.The chromyl chloride test is specific for the presence of chloride ions $(Cl^{-})$,where $X$ reacts with $K_2Cr_2O_7$ and concentrated $H_2SO_4$ to evolve reddish-brown vapors of chromyl chloride $(CrO_2Cl_2)$.Since the salt $X$ contains both $Fe^{3+}$ and $Cl^{-}$ ions,the salt is $FeCl_3$.

$LIST$-$I$ (Precipitating reagent and conditions)	$LIST$-$II$ (Cation)
$A$. $NH_4Cl + NH_4OH$	$I$. $Mn^{2+}$
$B$. $NH_4OH + (NH_4)_2CO_3$	$II$. $Pb^{2+}$
$C$. $NH_4OH + NH_4Cl + H_2S$ gas	$III$. $Al^{3+}$
$D$. Dilute $HCl$	$IV$. $Sr^{2+}$

An aqueous solution of a salt $X$ turns blood red on treatment with $CNS^{-}$ and blue on treatment with $K_4[Fe(CN)_6]$. $X$ also gives a positive chromyl chloride test. The salt $X$ is

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