An aqueous solution of sodium nitrite on boil | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorin

Vedclass · Accepted Answer

Nitroethane

Vedclass · Answer

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorine atom by the nitrite group,followed by decarboxylation upon boiling. The reaction proceeds as follows: $CH_3CHClCOONa + NaNO_2 \rightarrow CH_3CH(NO_2)COONa + NaCl$ Upon boiling,the intermediate undergoes decarboxylation: $CH_3CH(NO_2)COONa \xrightarrow{\Delta} CH_3CH_2NO_2 + CO_2 + NaCl$ Thus,the final product is nitroethane.

An aqueous solution of sodium nitrite on boiling with $\alpha$-chlorosodium propionate gives:

Similar Questions

The structure of the functional group of a secondary amide is:

Which of the following represents the azo group?

Tertiary butylamine is a ..........

What is the common name of the compound $CH_2 = CH - CH_2 - NH_2$?

The following compounds can be classified as $N,N$-dimethylpropan$-1-$amine,$N$-methylaniline,and aniline,respectively. Identify their classification as primary,secondary,or tertiary amines.

Vedclass Test Series

Exam Paper Generator

Online Exam Module