An atom has x energy levels,then the total nu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When an electron transitions from an excited state $x$ to lower energy levels,the total number of spectral lines is calculated by summing the poss

Vedclass · Accepted Answer

$1 + 2 + 3 + \dots + (x - 1)$

Vedclass · Answer

(C) When an electron transitions from an excited state $x$ to lower energy levels,the total number of spectral lines is calculated by summing the possible transitions from each level.For an atom with $x$ energy levels,the transitions are from level $x$ to $(x-1), (x-2), \dots, 1$.The number of lines is given by the sum: $(x-1) + (x-2) + (x-3) + \dots + 2 + 1$.This is equivalent to the sum of the first $(x-1)$ natural numbers,which is $1 + 2 + 3 + \dots + (x - 1)$.

An atom has $x$ energy levels,then the total number of spectral lines in its emission spectrum is given by:

Similar Questions

The ratio of velocity of electron in the second orbit of $He^{+}$ to the third orbit of $B^{4+}$ is $:-$

If $\lambda_0$ and $\lambda$ are respectively the threshold wavelength and wavelength of incident light,the velocity of photoelectrons ejected from the metal surface is

What is the ratio of the time period of revolution of an electron in the second orbit of a hydrogen atom to that in the third orbit of a $He^{+}$ ion?

When $\beta$-particles are sent through a tin metal foil,most of them go straight through the foil as

$A$ bulb is rated at $150 \text{ W}$, converting $8\%$ of its energy into light. If the energy of one photon is $4.42 \times 10^{-19} \text{ J}$, how many photons are emitted by the bulb per second?

Vedclass Test Series

Exam Paper Generator

Online Exam Module